Cho\(a,b,c\ge0;a+b+c\ge abc\)
CMR \(a^2+b^2+c^2\ge\sqrt{3}abc\)
HELP ME!!!!!!!!!!!!!
\(a,b,c\ge0\)
CMR: \(a^2+b^2+c^2\ge\sqrt{abc}.\left(\sqrt{a}+\sqrt{b}+\sqrt{c}\right)\)
Cho a, b, c \(\ge\)0 và a + b + c \(\ge\)abc
CMR : a2 + b2 + c2 \(\ge\)abc
cho a,b,c>0 ; abc=2.CMR
\(a^3+b^3+c^3\ge a\sqrt{b+c}+b\sqrt{c+a}+c\sqrt{a+b}\)
cho abc=1 .CMR (a+b)(b+c)(c+a)\(\ge\)2(a+b+c+1)
a, b, c > 0 thỏa a + b + c = abc. CMR:\(a^2+b^2+c^2\ge\sqrt{3}abc\)
Bài toán :
Cho a, b, c \(\ge\)0 và a + b + c \(\ge\)abc
CMR : a2 + b2 + c2 \(\ge\)abc
CMR nếu a,b,c \(\ge0\) thỏa mãn ab+bc+ca=3 thì \(\frac{1}{abc}+\frac{4}{\left(a+b\right)\left(b+c\right)\left(c+a\right)}\ge\frac{3}{2}\)
cho a,b,c>0;\(a+b+c,abc=1\).CMR
\(\dfrac{bc}{a^2\left(b+c\right)}+\dfrac{ca}{b^2\left(c+a\right)}+\dfrac{ab}{c^2\left(a+b\right)}\ge\dfrac{3}{2}\)