Ta có:a+b=23\(\Rightarrow\)(a+b)2=232
\(\Rightarrow\)(a+b)2=529\(\Rightarrow\)a2+2ab+b2=529
\(\Rightarrow\)a2+b2=529-2.132
\(\Rightarrow\)a2+b2=529-264\(\Rightarrow a^2+b^2=265\)
Ta có: (a+b)^2=a^2+2ab+b^2
Thay a+b=23 ,a.b=132 vào biểu thức ta có:
23^2=a^2+b^2+2.132
529=a^+b^2+264
529-264=a^2+b^2
265 =a^2+b^2
Vậy a^2+b^2=265
k mik nha bạn