ta có dạng tổng quát sau : 1/ 2 = 1/(2*1)
1/6 = 1/(2*3)
1/12 = 1/(3*4)
....................
1/n = 1/(x-1)x
cộng vế theo vế ta có :
\(A=\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+.....+\frac{1}{x\left(x-1\right)}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.......+\frac{1}{\left(x-1\right)}-\frac{1}{x}\)
\(=1-\frac{1}{x}\)
Mà A = 49/50
Nên \(1-\frac{1}{x}=\frac{49}{50}\)
\(\frac{1}{x}=1-\frac{49}{50}=\frac{1}{50}\)
\(x=50\)
\(n=x\left(x-1\right)=50\times49=2450\)
Vậy n = 2450
