\(PTHH:2Al+6HCl-^{t^o}>2AlCl_3+3H_2\)
0,2---->0,6-------->0,2--------->0,3 (mol)
\(n_{Al}=\dfrac{m}{M}=\dfrac{5,4}{27}=0,2\left(mol\right)\)
\(m_{HCl}=n\cdot M=0,6\cdot\left(1+35,5\right)=21,9\left(g\right)\)
\(m_{AlCl_3}=n\cdot M=0,2\cdot\left(27+35,5\cdot3\right)=26,7\left(g\right)\)
\(m_{H_2}=n\cdot M=0,3\cdot2=0,6\left(g\right)\)