\(\text{PTHH: }Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)
\(0,1\)____\(0,6\)
\(\text{a) }n_{Al_2O_3}=\frac{10,2}{102}=0,1\left(\text{mol}\right)\)
\(m_{HCl}=\frac{9,125\times400}{100}=36,5\left(\text{g}\right)\)
\(n_{HCl}=\frac{36,5}{36,5}=1\left(\text{mol}\right)\)
\(\text{So sánh tỉ lệ: }\frac{0,1}{1}