Question

câu c)

Answer 1

\(\dfrac{2\sqrt{3}+3\sqrt{2}}{\sqrt{3}+\sqrt{2}}-4\sqrt{\dfrac{3}{2}}-\dfrac{5}{1-\sqrt{6}}=\dfrac{\sqrt{6}\left(\sqrt{3}+\sqrt{2}\right)}{\sqrt{3}+\sqrt{2}}-2\sqrt{6}-\dfrac{5\left(1+\sqrt{6}\right)}{1-6}=\sqrt{6}-2\sqrt{6}+1+\sqrt{6}=1\)