21:
a: \(\in\)
b: \(\notin\)
23:
a: \(=\dfrac{5}{4}-\dfrac{5}{6}:\dfrac{9-4}{24}+\dfrac{11}{12}\)
\(=\dfrac{5}{4}-\dfrac{5}{6}\cdot\dfrac{24}{5}+\dfrac{11}{12}\)
\(=\dfrac{26}{12}-4=\dfrac{26-48}{12}=\dfrac{-22}{12}=\dfrac{-11}{6}\)
b: \(\Leftrightarrow x-\dfrac{3}{5}=\dfrac{2}{5}\cdot\dfrac{-1}{3}=\dfrac{-2}{15}\)
=>x=-2/15+3/5=-2/15+9/15=7/15