\(\dfrac{2}{5\times7}+\dfrac{2}{7\times9}+...+\dfrac{2}{13\times15}\)
=\(\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{13}-\dfrac{1}{15}\)
=\(\dfrac{1}{5}-\dfrac{1}{15}\)
=\(\dfrac{2}{15}\)
Chọn A
Ta có: \(\dfrac{2}{5\cdot7}+\dfrac{2}{7\cdot9}+\dfrac{2}{9\cdot11}+...+\dfrac{2}{13\cdot15}\)
\(=\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}\)
\(=\dfrac{1}{5}-\dfrac{1}{15}=\dfrac{2}{15}\)
\(\dfrac{2}{5\times7}+\dfrac{2}{7\times9}+\dfrac{2}{9\times11}+\dfrac{2}{11\times13}+\dfrac{2}{13\times15}\)
⇔ \(\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}\)
⇔ \(\dfrac{1}{5}-\dfrac{1}{15}\)
⇔ \(\dfrac{2}{15}\)
Câu này chọn đáp án A
Ta có: =15−17+17−19+19−111+111−113+113−115