Question

Câu 2 ạ

Answer 1

Câu 2 :

\(\text{Khí thoát ra là metan} \Rightarrow V_{CH_4} = 3,36(lít)\\ n_{CH_4} = \dfrac{3,36}{22,4} = 0,15(mol)\\ n_{C_2H_4} = a(mol) ; n_{C_3H_4} = b(mol) \\ \Rightarrow a + b = \dfrac{5,6}{22,4}-0,15 = 0,1(1)\\ C_2H_4 + Br_2 \to C_2H_4Br_2\\ C_3H_4 + 2Br_2 \to C_3H_4Br_4\\ n_{Br_2} = a + 2b = \dfrac{24}{160} = 0,15(2)\\ (1)(2)\Rightarrow a = 0,05 ; b = 0,05\\ V_{C_2H_4} = V_{C_3H_4} =0,05.22,4 = 1,12(lít)\)