Question

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Answer 1

\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-3=0\\x+\dfrac{3}{4}=\dfrac{5}{6}\\x+\dfrac{3}{4}=-\dfrac{5}{6}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\\x=\dfrac{1}{12}\\x=-\dfrac{19}{12}\end{matrix}\right.\)