Question

Cần gấp lắm giúp em mn ơi

Answer 1

\(\dfrac{2}{3x}\)

Answer 2

\(=\dfrac{2x+6}{3x\left(x+3\right)}=\dfrac{2\left(x+3\right)}{3x\left(x+3\right)}=\dfrac{2}{3x}\)

Answer 3

\(\dfrac{2}{3x+9}+\dfrac{2}{x^2+3x}\)

=\(\dfrac{2}{3\left(x+3\right)}+\dfrac{2}{x\left(x+3\right)}\)

=\(\dfrac{4}{3+x}\)

Answer 4

= 2 x + 6 / 3 x ( x + 3 ) = 2 ( x + 3 ) / 3 x ( x + 3 ) = 2 / 3x