a: \(=-\dfrac{3^{10}\cdot5^{21}}{5^{20}\cdot3^{12}}=-5\cdot\dfrac{1}{9}=-\dfrac{5}{9}\)
b: \(=-\dfrac{11^5}{11^5}\cdot\dfrac{13^7}{13^8}=-\dfrac{1}{13}\)
c: \(=\dfrac{2^{10}\cdot3^9\cdot\left(3-1\right)}{2^9\cdot3^{10}}=\dfrac{2^{11}\cdot3^9}{2^9\cdot3^{10}}=\dfrac{4}{3}\)
d: \(=\dfrac{5^{11}\cdot7^{11}\cdot8}{5^{11}\cdot7^{11}\cdot\left(5\cdot7+9\right)}=\dfrac{8}{35+9}=\dfrac{8}{44}=\dfrac{2}{11}\)