can gap a hua k
\(=\left(-\dfrac{10}{3}-\dfrac{1}{6}\right)+\left(\dfrac{13}{10}+\dfrac{7}{10}\right)=-\dfrac{7}{2}+2=-\dfrac{3}{2}\)
`-10/3 + 13/10 - 1/6 + 7/10`
`= (-10/3 - 1/6) + (13/10 + 7/10)`
`= -7/2 + 20/10`
`= -7/2 + 2`
`= -7/2 + 4/2`
`= -3/2`
\(-\dfrac{10}{3}+\dfrac{13}{10}-\dfrac{1}{6}+\dfrac{1}{7
}\)
=\(\left(-\dfrac{10}{3}-\dfrac{1}{6}\right)+\left(\dfrac{13}{10}+\dfrac{7}{10}\right)\)
=\(-\dfrac{7}{2}+\dfrac{20}{10}\)
=\(-\dfrac{7}{2}+2\)
=\(-\dfrac{7}{2}+\dfrac{4}{2}\)
=\(-\dfrac{3}{2}\)
giup em dc ko a em dang can gap a ko can ve hinh dau a
