Question

cân bằng các phương chình sau 

FeO + H₂SO_{4 -->} Fe₂(SO₄)+ H₂S+ H₂O

Answer 1

\(2\overset{+2}{Fe}\rightarrow2\overset{+3}{Fe}+2e\)	\(\times4\)
\(\overset{+6}{S}+8e\rightarrow\overset{-2}{S}\)	\(\times1\)

\(8FeO+13H_2SO_4\rightarrow4Fe_2\left(SO_4\right)_3+H_2S+12H_2O\)

Answer 2

\(8FeO+13H_2SO_4\rightarrow4Fe_2\left(SO_4\right)_3+H_2S\uparrow+12H_2O\)

Quá trình nhường-nhận electron:

\(\begin{matrix}Fe^{2+}\rightarrow Fe^{3+}+e\\S^{+6}+8e\rightarrow S^{-2}\end{matrix}\text{|}\begin{matrix}\times4\\\times1\end{matrix}\)

Answer 3

2FeO+4H2SO4---> Fe2(SO4)3+4H2O+SO2