Question

Các bạn giúp mình làm vs ạ 

Answer 1

Bài 5:

a: ĐKXĐ: a>0; a<>1; a<>4

b: \(B=\dfrac{\sqrt{a}-\sqrt{a}+1}{\sqrt{a}\left(\sqrt{a}-1\right)}:\dfrac{a-1+a-4}{\left(\sqrt{a}-2\right)\left(\sqrt{a}-1\right)}\)

\(=\dfrac{1}{\sqrt{a}\left(\sqrt{a}-1\right)}\cdot\dfrac{\left(\sqrt{a}-2\right)\left(\sqrt{a}-1\right)}{2a-5}\)

\(=\dfrac{\sqrt{a}-2}{\sqrt{a}\left(2a-5\right)}\)