Question

c, \(\dfrac{4}{9}.\dfrac{-7}{26}+\dfrac{45}{-26}.\dfrac{4}{7}+\dfrac{1}{3}\)

\(d,\left(\dfrac{5}{6}-\dfrac{1}{4}\right):\left(\dfrac{1}{2}+\dfrac{2}{3}\right)\)

\(e,\dfrac{8}{17}:\dfrac{-15}{16}+\dfrac{9}{17}:\dfrac{-15}{16}\)

\(f,25\%-1\dfrac{1}{2}:\left(-2022\right)^0+0,5.\dfrac{12}{5}\)

Answer 1

c: \(=\dfrac{-28}{9\cdot26}+\dfrac{-45\cdot4}{26\cdot7}+\dfrac{1}{3}\)

\(=\dfrac{-28}{234}+\dfrac{-180}{182}+\dfrac{1}{3}\)

\(=\dfrac{-635}{819}\)

d: \(=\dfrac{10-3}{12}:\dfrac{3+4}{6}=\dfrac{7}{12}\cdot\dfrac{6}{7}=\dfrac{1}{2}\)

e: \(=\dfrac{-16}{15}\left(\dfrac{8}{17}+\dfrac{9}{17}\right)=-\dfrac{16}{15}\)

Answer 2

\(c,=-\dfrac{14}{117}-\dfrac{90}{91}+\dfrac{1}{3}=\dfrac{-14.91-90.117+1729}{5187}=\dfrac{-635}{819}\\ d,=\left(\dfrac{5.4-6}{24}\right):\left(\dfrac{3+4}{6}\right)=\dfrac{7}{12}:\dfrac{7}{6}=\dfrac{1}{2}\\ e,=\left(\dfrac{8}{17}+\dfrac{9}{17}\right):\dfrac{-15}{16}=1:-\dfrac{15}{16}=-\dfrac{16}{15}\\ f,=\dfrac{1}{4}-\dfrac{3}{2}:1+\dfrac{1}{2}.\dfrac{12}{5}=\dfrac{1}{4}-\dfrac{3}{2}+\dfrac{6}{5}=\dfrac{5-30+25}{20}=-\dfrac{1}{20}\)