`@` `\text {Ans}`
`\downarrow`
`c)`
`(12x - 4^3) * 8^3 = 4*8^4`
`=> 12x - 4^3 = 4*8^4 \div 8^3`
`=> 12x - 4^3 = 4*8`
`=> 12x - 2^6 = 2^2 * 2^3`
`=> 12x - 2^6 = 2^5`
`=> 12x = 2^5 + 2^6`
`=> 12x = 96`
`=> x = 96 \div 12`
`=> x = 8`
Vậy, `x = 8.`
=>(12x-64)=4*8^4/8^3=4*8=32
=>12x=96
=>x=8