\(\frac{3-2x}{3}=\frac{5-7y}{5}\\ \Rightarrow\left(3-2x\right)\cdot5=\left(5-7y\right)\cdot3\)
\(\Rightarrow15-10x=15-21y\)
hay 10x=21y
\(\Rightarrow\frac{x}{21}=\frac{y}{10}hay\\ \)\(\frac{x}{y}=\frac{21}{10}\)
Ta có : \(\frac{3-2x}{3}=\frac{5-7y}{5}\)
\(\Leftrightarrow5\left(3-2x\right)=3\left(5-7y\right)\)
\(\Leftrightarrow15-10x=15-21y\)
\(\Leftrightarrow10x=21y\)
\(\Leftrightarrow\frac{x}{21}=\frac{y}{10}\Leftrightarrow\frac{x}{y}=\frac{21}{10}\)