Question

biến đổi thành hằng đẳng thức\(^{x^2+4x+4}\)

Answer 1

BBieesn đổi hằng đẳng thức 

x²+4x+4

=x²+2.2x+2²

=(x+2)²

Answer 2

Ta có:

\(x^2+4x+4\)

\(=x^2+2.2x+2^2\)

\(=\left(x+2\right)^2\)

Answer 3

Ta có : x² + 4x + 4 = (x + 2)²

Answer 4

\(x^2+4x+4\)

\(=x^2+2.2x+2^2\)

\(=\left(x+2\right)^2\)

Answer 5

x² + 4x + 4

= x² + 2.2x + 4

= ( x + 2 )² 

Answer 6

\(x^2+4x+4=x^2+2.x.2+2^2=\left(x+2\right)^2\)

Answer 7

x² + 4x +4 

=x² + 2.2x +2²

=(x+2)²

Answer 8

\(x^2+4x+4=\left(x+2\right)^2\)

Answer 9

x^2+4x+4=(x+2)^2

Answer 10

\(x^2+4x+4\)

\(=x^2+2.2x+2^2\)

\(=\left(x+2\right)^2\)

Answer 11

x²+4x+4 = (x+2)²