Lời giải :
\(\sqrt{10}+\sqrt{5}+1>\sqrt{9}+\sqrt{4}+1=3+2+1=6\)
\(\sqrt{35}< \sqrt{36}=6\)
Từ đây ta có : \(\sqrt{10}+\sqrt{5}+1>6>\sqrt{35}\)
Vậy \(\sqrt{10}+\sqrt{5}+1>\sqrt{35}\)
Ta có: \(\sqrt{10}>\sqrt{9}=3;\sqrt{5}>\sqrt{4}=2\)
\(\Rightarrow\sqrt{10}+\sqrt{5}+1>3+2+1=6\)
Mà \(6=\sqrt{36}>\sqrt{35}\)(do 36>35)
\(\Rightarrow\sqrt{10}+\sqrt{5}+1>\sqrt{35}\)
\(\sqrt{10}+\sqrt{5}+1\)
\(>\sqrt{9}+\sqrt{4}+1\)
\(=3+2+1=6=\sqrt{36}>\sqrt{35}\)
Vậy: \(\sqrt{10}+\sqrt{4}+1>\sqrt{35}\)
#HọcTốt!