Question

Bài 7: Tính PTK các chất có CTHH sau

a/ Al(OH)₃

b/ Ca₃(PO₄)₂

c/ Mg(NO₃)₂

d/ Fe(OH)₂

Answer 1

â) 78

b) 310

c) 148

d) 90

Answer 2

a/ Al(OH)₃ = 27+17.3 = 78

b/ Ca₃(PO₄)₂ = 40.3+2.(31+16.4) = 310

c/ Mg(NO₃)₂ = 24+2.(14+16.3) = 148

d/ Fe(OH)₂ = 56+17.2 = 90

Answer 3

\(a,PTK_{Al\left(OH\right)_3}=27+\left(16+1\right)\cdot3=78\left(đvC\right)\\ b,PTK_{Ca_3\left(PO_4\right)_2}=40\cdot3+\left(31+16\cdot4\right)\cdot2=310\left(đvC\right)\\ c,PTK_{Mg\left(NO_3\right)_2}=24+\left(14+16\cdot3\right)\cdot2=148\left(đvC\right)\\ d,PTK_{Fe\left(OH\right)_2}=56+\left(16+1\right)\cdot2=90\left(đvC\right)\)