\(a.\left(35-815\right)-\left(795-65\right)\\ =35-815-795+65\\ =\left(35+65\right)-\left(815+795\right)\\ =100-1610=-1510\)
Bài 2:
a: Ta có: \(\left(35-815\right)-\left(795-65\right)\)
\(=35-815-795+65\)
\(=100-1600\)
=-1500
b: Ta có: \(5-197-2015-2015\)
\(=-2010-2212\)
=-4222
c: Ta có: \(1259-1409-12+1259+1409\)
\(=2518-12\)
=2506