Question

bài 2:     1, \(\left(\dfrac{5}{6}\right)^{10}.\left(\dfrac{3}{10}\right)^{10}\)2,\(\left(\dfrac{4}{7}\right)^{19}:\left(\dfrac{-12}{35}\right)^{19}\) 3,\(\left(\dfrac{-3}{7}\right)^7:\left(\dfrac{-3}{5}\right)\) 

Answer 1

Lời giải:

1.

$(\frac{5}{6})^{10}.(\frac{3}{10})^{10}=(\frac{5}{6}.\frac{3}{10})^{10}=(\frac{1}{4})^{10}$

$=\frac{1}{4^{10}}$

2.

$(\frac{4}{7})^{19}: (\frac{-12}{35})^{19}=(\frac{4}{7}: \frac{-12}{35})^{19}=(\frac{-5}{3})^{19}$

3.

$(\frac{-3}{7})^7:\frac{-3}{5}=\frac{(-3)^7}{7^7}.\frac{5}{-3}=\frac{5.(-3)^6}{7^7}=\frac{5.3^6}{7^7}$

Answer 2

giúp mình với ạ

 

 

Answer 3

1) \(\left(\dfrac{5}{6}\right)^{10}\cdot\left(\dfrac{3}{10}\right)^{10}\)

\(=\left(\dfrac{5}{6}\cdot\dfrac{3}{10}\right)^{10}\)

\(=\left(\dfrac{1}{4}\right)^{10}\)

2) \(\left(\dfrac{4}{9}\right)^{19}:\left(\dfrac{-12}{35}\right)^{19}\)

\(=\left(\dfrac{4}{9}:\dfrac{-12}{35}\right)^{19}\)

\(=\left(\dfrac{4}{9}\cdot\dfrac{35}{-12}\right)^{19}\)

\(=\left(-\dfrac{35}{27}\right)^{19}\)

3) \(\left(\dfrac{-3}{7}\right)^7:\left(\dfrac{-3}{5}\right)^7\)

\(=\left(\dfrac{-3}{7}:\dfrac{-3}{5}\right)^7\)

\(=\left(\dfrac{-3}{7}\cdot\dfrac{5}{-3}\right)^7\)

\(=\left(\dfrac{5}{7}\right)^7\)