Question

bài 10:

1) ( 6 mũ 2007-6 mũ 2006): 6 mũ 2006

2) ( 5 mũ 1986 - 5 mũ 1985); 5 mũ 1985

Answer 1

1: \(=\dfrac{6^{2006}\left(6-1\right)}{6^{2006}}=5\)

2: \(=\dfrac{5^{1985}\left(5-1\right)}{5^{1985}}=4\)

Answer 2

`(6^2007 - 6^2006) : 6^2006`

`=6^2007 : 6^2006 - 6^2006 : 6^2006`

`=6^1 - 6^0`

`=6-1`

`=5`

__________________________________

`(5^1986 - 5^1985) : 5^1985`

`=5^1986: 5^1985 - 5^1985 : 5^1985`

`=5^1 - 5^0`

`=5-1`

`=4`

Answer 3

`a, 6^2006 . (6+1) : 6^2006`

`= 7`

`b, = 5^1985(5 + 1) : 5^1985`

`= 6`