Bài 1 :
a, \(\left(x^2-29\right)^3=343\)
=> \(\left(x^2-29\right)^3=7^3\)
=> \(x^2-29=7\)
=> \(x^2=7+29=36\)
=> \(\orbr{\begin{cases}x=6\\x=-6\end{cases}}\)
Do x là số tự nhiên => x = 6
b, \(2^{x+2}+2^{x-1}+2^{x-2}=152\)
=> \(2^x.2^2+2^x:2^1+2^x:2^2=152\)
=> \(2^x.2^2+2^x.\frac{1}{2}+2^x.\frac{1}{4}=152\)
=> \(2^x.\left(2^2+\frac{1}{2}+\frac{1}{4}\right)=152\)
=> \(2^x.\frac{19}{4}=152\)
=> \(2^x=32\)
=> \(2^x=2^5\)
=> x = 5
Bài 2 :
a, \(\left(2^9.76+2^{10}.35\right).3=2^{10}.38+2^{10}.35=2^{10}\left(38+35\right).3=2^{10}.73.3=1024.3.73=224256\)
b, \(\frac{\left(2^9.76+2^{10}.35\right).3}{2^8.438}=\frac{2^{10}.73.3}{2^9.219}=\frac{2^{10}.219}{2^9.219}=2\)
