Question

 Bài 1: tìm x

6x²-2x(3x+3/2)=9

Answer 1

\(6x^2-2x\left(3x+\dfrac{3}{2}\right)=9\)

\(\Rightarrow6x^2-6x^2-3x=9\)

\(\Rightarrow-3x=9\)

\(\Rightarrow x=\dfrac{9}{-3}\)

\(\Rightarrow x=-3\)

Answer 2

\(6x^2-2x\left(3x+\dfrac{3}{2}\right)=9\\ \Leftrightarrow6x^2-6x^2-3x=9\\ \Leftrightarrow3x=9\\ \Leftrightarrow x=3\)

Answer 3

\(6x^2-2x\left(3x+\dfrac{3}{2}\right)=9\\ \Rightarrow6x^2-\left(6x^2+3x\right)=9\\ \Rightarrow6x^2-6x^2-3x=9\\ \Rightarrow-3x=9\\ \Rightarrow x=9:-3\\ \Rightarrow x=-3\)

Answer 4

x = -3