Question

Bài 1: rút gọn

\(\dfrac{7x^{2^{ }}-14x+7}{3x^2-3x}\)

Answer 1

\(\dfrac{7x^2-14x+7}{3x^2-3x}=\dfrac{7\left(x^2-2x+1\right)}{3x\left(x-1\right)}=\dfrac{7\left(x-1\right)^2}{3x\left(x-1\right)}=\dfrac{7\left(x-1\right)}{3x}\)

Answer 2

\(=\dfrac{7\left(x^2-2x+1\right)}{3x\left(x-1\right)}=\dfrac{7\left(x-1\right)^2}{3x\left(x-1\right)}=\dfrac{7\left(x-1\right)}{3x}\)

Answer 3

\(\dfrac{7x^2-14x+7}{3x^2-3x}=\dfrac{7\left(x^2-2x+1\right)}{3x\left(x-1\right)}=\dfrac{7\left(x-1\right)^2}{3x\left(x-1\right)}=\dfrac{7\left(x-1\right)}{3x}\)

Answer 4

\(=\dfrac{7\left(x^2-2x+1\right)}{3x\left(x-1\right)}=\dfrac{7\left(x-1\right)^2}{3x\left(x-1\right)}=\dfrac{7\left(x-1\right)}{3x}\)