Question

 bài 1 phá giá trị tuyết đối :  /4x -2/ 

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Answer 1

\(\left|4x-2\right|=\left[{}\begin{matrix}4x-2\left(x>=\dfrac{1}{2}\right)\\2-4x\left(x< \dfrac{1}{2}\right)\end{matrix}\right.\)

Answer 2

\(\left|4x-2\right|=>\left[{}\begin{matrix}2-4x\left(x< \dfrac{1}{2}\right)\\4x-2\left(x\ge\dfrac{1}{2}\right)\end{matrix}\right.\)