Bài 1: Giải các phương trình sau
a,\(\frac{4x-8}{2x^2+1}\)= 0
b, \(\frac{x^2-x-6}{x-3}\)= 0
c,\(\frac{x+5}{3x-6}\)- \(\frac{1}{2}\)=\(\frac{2x-3}{2x-4}\)
d, \(\frac{12}{1-9x^2}\)= \(\frac{1-3x}{1+3x}\)- \(\frac{1+3x}{1-3x}\)
e, \(\frac{x+5}{x-1}\)= \(\frac{x+1}{x-3}\)- \(\frac{8}{x^2-4x+3}\)
f, \(\frac{x+1}{x-2}\)- \(\frac{5}{x+2}\)= \(\frac{12}{x^2-4}\)+1
g, \(\frac{2x-5}{x-2}\)- \(\frac{3x-5}{x+1}\)= -1
a) \(\frac{4x-8}{2x^2+1}=0\)
\(\Rightarrow4x-8=0\left(2x^2+1\ne0\right)\)
\(\Leftrightarrow4x=8\)
\(\Leftrightarrow x=2\)
Vậy x=2
b)
\(\frac{x^2-x-6}{x-3}=0\)
\(\Leftrightarrow\frac{\left(x-3\right)\left(x+2\right)}{x-3}=0\)
\(\Rightarrow x+2=0\)
\(\Leftrightarrow x=-2\)
Vậy x=-2
