\(f\left(x\right)=2x^2+5x-3\)
f(1)=2+5-3=4
f(0)=-3
f(1,5)=2x2,25+5x1,5-3=9
\(f\left(x\right)=2x^2+5x-3\)
\(f\left(1\right)=2.1^2+5.1-3=2+5-3=4\)
\(f\left(0\right)=-3\)
\(f\left(1,5\right)-2.\left(1,5\right)^2+5.1,5-3=9\)
f(x) = 2x2 + 5x -3
f(1) = 2.12 + 5.1 - 3 = 2.1 + 5.1 - 3 = 4
f(0) = 2.02 + 5.0 - 3 = -3
f(1,5) = 2 . 1,52 + 5 . 1,5 - 3 = 9