a: \(\left(x+1,5\right):3\dfrac{1}{5}=-\dfrac{5}{8}\)
=>\(\left(x+1,5\right):\dfrac{16}{5}=-\dfrac{5}{8}\)
=>\(x+\dfrac{3}{2}=-\dfrac{5}{8}\cdot\dfrac{16}{5}=\dfrac{-16}{8}=-2\)
=>\(x=-2-\dfrac{3}{2}=-\dfrac{7}{2}\)
b: \(\left(8\dfrac{4}{5}x-50\right):0,4=51\)
=>\(8,8x-50=0,4\cdot51=20,4\)
=>\(8,8x=20,4+50=70,4\)
=>\(x=\dfrac{70.4}{8.8}=8\)