Question

Ba(AlO₂)₂ + HCl \(\rightarrow\)

Answer 1

$Ba(AlO_2)_2 + 2HCl + 2H_2O \to 2Al(OH)_3 + BaCl_2$

Nếu $HCl$ dư : 

$Al(OH)_3 + 3HCl \to AlCl_3 + 3H_2O$

Answer 2

\(Ba\left(ALO_2\right)_2+2HCL+2H_2O\rightarrow2AL\left(OH\right)_3+BaCl_2\)

Nếu \(HCL.dư:\)

\(AL\left(OH\right)_3+3HCL\rightarrow ALCL_3+3H_2O\)