\(|x|=\dfrac{1}{2}\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\Rightarrow B=2.\left(\dfrac{1}{2}\right)^2-3.\dfrac{1}{2}+5=4\\x=-\dfrac{1}{2}\Rightarrow B=2.\left(-\dfrac{1}{2}\right)^2-3.\left(-\dfrac{1}{2}\right)+5=7\end{matrix}\right.\)
5, Tìm x, y ϵ Z, sao cho:
a) y = \(\dfrac{6x-4}{2x+3}\) b) \(\dfrac{1}{x}-\dfrac{y}{2}=\dfrac{1}{4}\)
c) xy-3x+2y=5 d) (3x-5)(2x+1)=12
Tìm x:
a) \(\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
b) \(\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
\(b,\dfrac{x}{2}-\left(\dfrac{3x}{5}-\dfrac{13}{5}\right)=-\left(\dfrac{7}{5}+\dfrac{7}{10}.x\right)\)
\(c,\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
\(d,\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
\(e,2\left(x-1\right)=\left(x-1\right)^2\)
Tìm số nguyên x:
1) A=\(\dfrac{-5}{x+2}\)
2) B=\(\dfrac{x+1
}{x-3}\)
3) C=\(\dfrac{3x+1}{x-2}\)
4) D=\(\dfrac{2x-1}{x+2}\)
Thu gọn các đơn thức đồng dạng trong đa thức sau:
a) \(A=x^5-\dfrac{1}{2}x+7x^3-2x+\dfrac{1}{5}x^3+3x^4-x^5+\dfrac{2}{5}x^4+15\)
b) \(B=3x^2-10+\dfrac{2}{5}x^3+7x-x^2+8+7x^2\)
c) \(C=\dfrac{1}{7}x-2x^4+5x+6\)
a)\([x.\dfrac{1}{2}]^{3}=\dfrac{1}{27}\)
b)\([x+\dfrac{1}{2} ]^{2}=\dfrac{4}{5} \)
c) I 3x-4/5 I = 11/5
d) I 2x - 2I = 0
a,2.(\(\dfrac{1}{4}\)+x)\(^3\)=(\(-\dfrac{27}{4}\))
b,(x+\(\dfrac{1}{2}\))\(^3\):3=\(\dfrac{-1}{81}\)
c,(\(\dfrac{2}{3}\)-x)\(^2\)=1:\(\dfrac{4}{9}\)
d,(2x-\(\dfrac{1}{5}\))\(^2\)+\(\dfrac{16}{25}\)=1
e,(\(\dfrac{2}{5}\)-3x)\(^2\)-\(\dfrac{1}{5}\)=\(\dfrac{4}{25}\)
7x^3-2x^2:-2x^2+(\(\dfrac{5}{4}\)x^2-3x):x-\(\dfrac{1}{2}\)x(x-1)(2x+1)
Tính giá trị của biểu thức sau:
a) \(3x-5y+1\) tại \(x=\dfrac{1}{3}\) ; \(y=-\dfrac{1}{5}\) b) \(3x^2-2x-5\) tại \(x=1\) ; \(x=-1\)
Cho 2 đơn thức
\(A\left(x\right)=-2x^3+11x^2-5x-\dfrac{1}{5}\)
\(B\left(x\right)=2x^3-3x^2-7x+\dfrac{1}{5}\)
a) Tính A(x) + B(x)
b) Tìm đa thức C(x) biết C(x) +B(x) = A(x)
