Ta có: \(\widehat{A}-\widehat{B}=\widehat{B}-\widehat{C}=10^0\)
\(\Rightarrow\widehat{A}+\widehat{C}=2\widehat{B}\)
\(\Rightarrow\widehat{A}+\widehat{B}+\widehat{C}=2\widehat{B}+\widehat{B}\)
\(\Rightarrow3\widehat{B}=180^0\Rightarrow\widehat{B}=60^0\)
\(\Rightarrow\left\{{}\begin{matrix}\widehat{A}=10^0+\widehat{B}=70^0\\\widehat{C}=\widehat{B}-10^0=50^0\end{matrix}\right.\)