\(a,71-3(12-x)=125\\3(12-x)=71-125\\3(12-x)=-54\\12-x=-54:3\\12-x=-18\\x=12-(-18)\\x=30\\---\)
\(b,3(12+x)-41=-50\\3(12+x)=-50+41\\3(12+x)=-9\\12+x=-9:3\\12+x=-3\\x=-3-12\\x=-15\\---\)
\((14+2x)-34=-28\\14+2x=-28+34\\14+2x=6\\2x=6-14\\2x=-8\\x=-8:2\\x=-4\\Toru\)
3(12 - x) = 71 - 125
3(12 - x) = -54
12 - x = -54 : 3
12 -x = -18
x = 12 + 18
x = 30
b) 3(12+x)- 41= -50
3(12 + x) = -50 + 41
3(12 - x) = -9
12 - x = -9 : 3
12 - x = -3
x = 12 + 3
x = 15
c)(14+2x)-34=-28
( 14 + 2x) = -28 + 34
(14 + 2x) = 6
2x = 6 - 14
2x = -8
x = -8 : 2
x = -4
--thonezz--
Tớ sửa lại câu b nhé 😥( tớ viết lộn đề :( )
b) 3(12+x)- 41= -50
3(12 + x) = -50 + 41
3(12 + x) = -9
12 + x = -9 : 3
12 + x = -3
x = -3 -12
x = -15