17 tháng 1 2022 lúc 16:18
Các câu hỏi tương tự
17 tháng 7 2023 lúc 13:12
a) \(\dfrac{2}{7}-\dfrac{8}{9}.x=\dfrac{2}{3}\)
b) \(\dfrac{2}{5}-\dfrac{2}{5}x=\dfrac{2}{5}\)
c) \(\dfrac{2}{9}-\dfrac{7}{8}x=\dfrac{1}{3}\)
Tìm x, biết:
a) \(\left(3\dfrac{1}{2}-2.x\right).3\dfrac{1}{3}=7\dfrac{1}{3}\)
b) \(\dfrac{4}{9}.x=\dfrac{9}{8}-0,125\)
c) \(\dfrac{-X}{21}=\dfrac{20}{7}\)
tìm x , biết:a) x : 4dfrac{1}{3} -2,5 b) dfrac{3}{5}x + dfrac{1}{4} dfrac{1}{10}c) 2dfrac{7}{9} - dfrac{12}{13}x dfrac{7}{9} d)dfrac{-2}{3}-dfrac{1}{3}left(2x-5right)dfrac{3}{2}
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tìm x , biết:
a) \(x\) : \(4\dfrac{1}{3}\) = -2,5 b) \(\dfrac{3}{5}x\) + \(\dfrac{1}{4}\) = \(\dfrac{1}{10}\)
c) \(2\dfrac{7}{9}\) \(-\) \(\dfrac{12}{13}x\) = \(\dfrac{7}{9}\) d)\(\dfrac{-2}{3}-\dfrac{1}{3}\)\(\left(2x-5\right)=\dfrac{3}{2}\)
Tìm x:
a) \(\dfrac{-x}{4}=\dfrac{-9}{x}\)
b) \(\dfrac{5}{9}+\dfrac{x}{-1}=\dfrac{-1}{3}\)
c) \(x:3\dfrac{1}{15}=1\dfrac{1}{2}\)
d) \(\dfrac{3x-1}{-5}=\dfrac{-5}{3x-1}\)
Bài 4. Tìm x biết:
a. \(\dfrac{x}{5}=\dfrac{2}{5},\dfrac{3}{8}=\dfrac{6}{x},\dfrac{1}{9}=\dfrac{x}{27}\)
b. \(\dfrac{4}{x}=\dfrac{8}{6},\dfrac{3}{x-5}=\dfrac{-4}{x+2},\dfrac{x}{-2}=\dfrac{-8}{x}\)
5 tháng 3 2022 lúc 17:37
So sánh dfrac{9}{170};dfrac{9}{230};dfrac{53}{144} Số nguyên x thỏa mãn left(dfrac{3}{4}-dfrac{2}{3}right)+dfrac{5}{6}le xledfrac{4}{5}-left(dfrac{3}{10}-dfrac{5}{4}right)A. x1 B. x0 C. x2 D. xinleft{0;1right} EM CẦN GẤP Ạ!
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So sánh \(\dfrac{9}{170};\dfrac{9}{230};\dfrac{53}{144}\)
Số nguyên \(x\) thỏa mãn \(\left(\dfrac{3}{4}-\dfrac{2}{3}\right)+\dfrac{5}{6}\le x\le\dfrac{4}{5}-\left(\dfrac{3}{10}-\dfrac{5}{4}\right)\)
A. \(x=1\) B. \(x=0\) C. \(x=2\) D. \(x\in\left\{0;1\right\}\)
EM CẦN GẤP Ạ!
Tìm x, biết:
a) dfrac{2}{5} + dfrac{3}{4}: x dfrac{-1}{2}
b) dfrac{5}{7} - dfrac{2}{3} . x dfrac{4}{5}
c) dfrac{1}{2} x + dfrac{2}{3} x dfrac{-2}{3}
d) dfrac{4}{7}x - x dfrac{-9}{14}
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Tìm x, biết:
a) \(\dfrac{2}{5}\) + \(\dfrac{3}{4}\): x = \(\dfrac{-1}{2}\)
b) \(\dfrac{5}{7}\) - \(\dfrac{2}{3}\) . x = \(\dfrac{4}{5}\)
c) \(\dfrac{1}{2}\) x + \(\dfrac{2}{3}\) x = \(\dfrac{-2}{3}\)
d) \(\dfrac{4}{7}\)x - x= \(\dfrac{-9}{14}\)
Tìm x nếu, \(\dfrac{-3}{x-1}\)+\(\dfrac{1}{x}\)+\(\dfrac{2}{x+2}=0\)
A.\(\dfrac{-2}{9}\) B.\(\dfrac{-2}{7}\) C.\(\dfrac{2}{8}\) D.\(\dfrac{2}{3}\) E.\(\dfrac{1}{5}\)
a) x + dfrac{2}{5} dfrac{1}{2}b) x - dfrac{2}{5} dfrac{2}{7}c) dfrac{3}{5} - x dfrac{1}{10}d) x . dfrac{3}{4} dfrac{9}{20}e) x : dfrac{1}{7} 14f) ( dfrac{1}{4} + x ) . dfrac{1}{2} dfrac{2}{5}g) x . dfrac{2}{3} - dfrac{2}{3} dfrac{9}{12}h) dfrac{3}{4} + dfrac{1}{4} : x dfrac{2}{5}k) 3dfrac{4}{5} - x dfrac{18}{5}l) x . 2dfrac{1}{3} dfrac{3}{4}m) x . dfrac{6}{11} + x . dfrac{5}{11} 2025n) x . dfrac{14}{9} - x . dfrac{7}{9} + x . dfrac{5}{9} 2Các bạn làm theo cách bình thường ở lớp...
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a) x + \(\dfrac{2}{5}\) = \(\dfrac{1}{2}\)
b) x - \(\dfrac{2}{5}\) = \(\dfrac{2}{7}\)
c) \(\dfrac{3}{5}\) - x = \(\dfrac{1}{10}\)
d) x . \(\dfrac{3}{4}\) = \(\dfrac{9}{20}\)
e) x : \(\dfrac{1}{7}\) = 14
f) ( \(\dfrac{1}{4}\) + x ) . \(\dfrac{1}{2}\) = \(\dfrac{2}{5}\)
g) x . \(\dfrac{2}{3}\) - \(\dfrac{2}{3}\) = \(\dfrac{9}{12}\)
h) \(\dfrac{3}{4}\) + \(\dfrac{1}{4}\) : x = \(\dfrac{2}{5}\)
k) \(3\dfrac{4}{5}\) - x = \(\dfrac{18}{5}\)
l) x . \(2\dfrac{1}{3}\) = \(\dfrac{3}{4}\)
m) x . \(\dfrac{6}{11}\) + x . \(\dfrac{5}{11}\) = 2025
n) x . \(\dfrac{14}{9}\) - x . \(\dfrac{7}{9}\) + x . \(\dfrac{5}{9}\) = 2
Các bạn làm theo cách bình thường ở lớp 5 cho mính nhé!
Chú ý: dấu "." là dấu nhân.
Tìm \(x\) biết:
\(a.x=\dfrac{1}{5}+\dfrac{-3}{7}\) \(b.\dfrac{3}{5}-\dfrac{4}{7}\div x=\dfrac{-9}{10}\) \(c.x-\left(\dfrac{-3}{4}\right)=\dfrac{-2}{3}-\dfrac{1}{2}\) \(d.\dfrac{-5}{9}-x=\dfrac{1}{3}+\dfrac{7}{18}\)