Ta có: \(\dfrac{3x^3+3x^2-1}{3x+1}\)
\(=\dfrac{3x^3+x^2+2x^2+\dfrac{2}{3}x-\dfrac{2}{3}x-\dfrac{2}{9}-\dfrac{7}{9}}{3x+1}\)
\(=\dfrac{3x^2\left(x+\dfrac{1}{3}\right)+2x\left(x+\dfrac{1}{3}\right)-\dfrac{2}{3}\left(x+\dfrac{1}{3}\right)-\dfrac{7}{9}}{3\left(x+\dfrac{1}{3}\right)}\)
\(=3x^2+2x-\dfrac{2}{3}-\dfrac{\dfrac{7}{9}}{3\left(x+\dfrac{1}{3}\right)}\)