\(\dfrac{-1}{4}:\dfrac{-3}{4}+\dfrac{1}{2}< x< \dfrac{7}{8}-\dfrac{1}{2}:\dfrac{-5}{6}\)
=>\(\dfrac{1}{3}+\dfrac{1}{2}< x< \dfrac{7}{8}+\dfrac{1}{2}\cdot\dfrac{6}{5}\)
=>\(\dfrac{5}{6}< x< \dfrac{7}{8}+\dfrac{3}{5}=\dfrac{59}{40}\)
mà x nguyên
nên x=1