\(=\left(\sqrt{11}+7\right)\sqrt{60-2.7\sqrt{11}}.\)
\(=\left(\sqrt{11}+7\right)\sqrt{\left(7-\sqrt{11}\right)^2}.\)
\(=\left(\sqrt{11}+7\right)\left(7-\sqrt{11}\right)=49-11=38.\)
\(=\left(\sqrt{11}+7\right)\sqrt{60-2.7\sqrt{11}}.\)
\(=\left(\sqrt{11}+7\right)\sqrt{\left(7-\sqrt{11}\right)^2}.\)
\(=\left(\sqrt{11}+7\right)\left(7-\sqrt{11}\right)=49-11=38.\)
Tính: \(\left(\sqrt{22}+7\sqrt{2}\right)\sqrt{30-7\sqrt{11}}\)
Rút gọn biểu thức sau:
\(A=\left(\sqrt{22}+7\sqrt{2}\right)\sqrt{30-7\sqrt{11}}\)
TÍNH:
\(\left(\sqrt{22}+7\sqrt{2}\right)\sqrt{30-7\sqrt{11}}\)
Rút gọn: (Giải chi tiết từng bước)
7) \(\left(\sqrt{28}-\sqrt{12}-\sqrt{7}\right)\sqrt{7}+2\sqrt{21}\)
8) \(\left(\sqrt{99}-\sqrt{18}-\sqrt{11}\right)\sqrt{11}+3\sqrt{22}\)
a) 11+6\(\sqrt{2}\) = \(\left(3+\sqrt{2}\right)^2\)
b) 8-2\(\sqrt{7}\)=\(\left(\sqrt{7}-1\right)^2\)
c)\(\sqrt{11+6\sqrt{2}}=\sqrt{11-6\sqrt{2}}=6\)
d) \(\sqrt{8-2\sqrt{7}}-\sqrt{8+2\sqrt{7}}=-2\)
Rút gọn các biểu thức sau
a \(\left(2\sqrt{3}+\sqrt{5}\right)\sqrt{3}-\sqrt{60}\)
b \(\left(5\sqrt{2}+2\sqrt{5}\right)\sqrt{5}-\sqrt{250}\)
c\(\left(\sqrt{28}-\sqrt{12}-\sqrt{7}\right)\sqrt{7}+2\sqrt{21}\)
d \(\left(\sqrt{99}-\sqrt{18}-\sqrt{11}\right)\sqrt{11}+3\sqrt{22}\)
\(1.\)\(\left(5\sqrt{2}+2\sqrt{5}\right)\sqrt{5}-\sqrt{250}\)\(\)
\(2.\)\(\left(\sqrt{28}-\sqrt{12}-\sqrt{7}\right)\sqrt{7}+2\sqrt{21}\)\(\)
\(3.\)\(\left(\sqrt{99}-\sqrt{18-\sqrt{11}}\right)\sqrt{11}+3\sqrt{22}\)
Đề : Tính
a) \(\left(5\sqrt{7}+7\sqrt{5}\right):\sqrt{35}\)
b) \(\left(2\sqrt{8}-3\sqrt{3}+1\right):\sqrt{6}\)
c) \(\left(\sqrt{99}-\sqrt{18}-\sqrt{11}\right):\sqrt{11}+3\sqrt{22}\)
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Rút gọn : \(A=\frac{\sqrt{7-2\sqrt{10}}\left(7+2\sqrt{10}\right)\left(74-22\sqrt{10}\right)}{\sqrt{125}-4\sqrt{50}+5\sqrt{20}+\sqrt{8}}\)