Câu 4:
\(\widehat{x'Oy'}=\widehat{xOy}=65^0\)
\(\widehat{x'Oy}=\widehat{xOy'}=180^0-65^0=115^0\)
Câu 5:
\(\widehat{x'Oy'}=\widehat{xOy}=75^0\)
\(\widehat{xOy'}=\widehat{x'Oy}=105^0\)
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