Question

ae giúp mình nha

Answer 1

Answer 2

\(\sqrt{3-2\sqrt{2}}=\sqrt{2}-1\)

Answer 3

a) \(\sqrt{3-2\sqrt{2}}=\sqrt{\left(\sqrt{2}-1\right)^2}=\sqrt{2}-1\)

b) \(\sqrt{12-6\sqrt{3}}=\sqrt{\left(\sqrt{9}-\sqrt{3}\right)^2}=3-\sqrt{3}\)

c) \(\sqrt{4\sqrt{5}+21}=\sqrt{\left(\sqrt{20}+1\right)}=\sqrt{20}+1\)

d) \(\sqrt{11+4\sqrt{7}}=\sqrt{\left(\sqrt{7}+\sqrt{4}\right)^2}=\sqrt{7}+\sqrt{4}\)

Answer 4

b: \(\sqrt{12-6\sqrt{3}}=3-\sqrt{3}\)

c: \(\sqrt{21+4\sqrt{5}}=2\sqrt{5}+1\)

d: \(\sqrt{11+4\sqrt{7}}=2+\sqrt{7}\)