ΔABC vuông tại A ta có:
\(sinB=\dfrac{AC}{BC}=\dfrac{7}{\sqrt{74}}=\dfrac{7\sqrt{74}}{74}=>cosC=\dfrac{7\sqrt{74}}{74}\\ cosB=\dfrac{AB}{BC}=\dfrac{5}{\sqrt{74}}=\dfrac{5\sqrt{74}}{74}=>sinC=\dfrac{5\sqrt{74}}{74}\\ tanB=\dfrac{AC}{AB}=\dfrac{7}{5}=>cotC=\dfrac{7}{5}\\ cotB=\dfrac{AB}{AC}=\dfrac{5}{7}=>tanC=\dfrac{5}{7}\)