a) Ta có: \(\dfrac{5}{8}x=\dfrac{3}{2}\)
\(\Leftrightarrow x=\dfrac{3}{2}:\dfrac{5}{8}=\dfrac{3}{2}\cdot\dfrac{8}{5}\)
hay \(x=\dfrac{12}{5}\)
Vậy: \(x=\dfrac{12}{5}\)
b) Ta có: \(y:\dfrac{1}{6}=\dfrac{3}{5}\)
\(\Leftrightarrow y=\dfrac{3}{5}\cdot\dfrac{1}{6}=\dfrac{3}{30}\)
hay \(y=\dfrac{1}{10}\)
Vậy: \(y=\dfrac{1}{10}\)
a,\(\dfrac{5}{8}\cdot y=\dfrac{3}{2}\\ y=\dfrac{3}{2}:\dfrac{5}{8}\\ y=\dfrac{12}{5}\)
\(b,y:\dfrac{1}{6}=\dfrac{3}{5}\\ y=\dfrac{3}{5}\cdot\dfrac{1}{6}\\ y=\dfrac{1}{10}\)
a) 5/8 x y =3/2
y=3/2:5/8
y=12/5
b) y:1/6=3/5
y =3/5x1/6
y =1/10