\(a\cdot\dfrac{3}{7}-\dfrac{246}{5}+a\cdot\dfrac{3}{5}=6\)
=>\(a\left(\dfrac{3}{7}+\dfrac{3}{5}\right)=6+\dfrac{246}{5}=\dfrac{30+246}{5}=\dfrac{276}{5}\)
=>\(a\cdot\dfrac{15+21}{35}=\dfrac{276}{5}\)
=>\(a\cdot\dfrac{36}{35}=\dfrac{276}{5}\)
=>\(a=\dfrac{276}{5}:\dfrac{36}{35}=\dfrac{161}{3}\)
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