Question

a, x+5=10-x

b.x+12=-5-x

Answer 1

a) x+5=10-x

<=> x+x=10-5

<=> 2x=5

<=> x=\(\frac{5}{2}\)

b) \(x+12=-5-x\)

\(\Leftrightarrow x+x=-5-12\)

\(\Leftrightarrow2x=-17\)

\(\Leftrightarrow x=\frac{-17}{2}\)

Answer 2

a, x+5=10-x

<=> x+x=10-5

<=> 2x=5

<=>x=5/2

Vậy x=5/2

b, x+12=-5-x

<=> x+x=-5-12

<=> 2x=-17

<=>x=-17/2

Vậy x=-17/2

Answer 3

        \(a,x+5=10-x\)

\(=>x+x=10-5\)

                   \(2x=5\)

               Vậy \(x=\frac{5}{2}\)

     \(b,x+12=-5-x\)

\(=>x+x=-5-12\)

                    \(2x=-17\)

                Vậy \(x=-\frac{17}{2}\)

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Answer 4

a,x+5=10-x

=>x+x=12-5

=>2x=7

=>x=2,5

b,x+12=-5-x

=>x+x=12+(-5)

=>2x=7

=>x=3,5