a)
\(\left(x+5\right)^3=-64=\left(-4\right)^3\)
=> x + 5 = -4
=> x = -9
b)
\(\left(2x-3\right)^2=9=\left(\pm3\right)^2\)
+) 2x - 3 = 3
2x = 6
x = 3
+) 2x - 3 = -3
2x = 0
x = 0
c)
\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(M=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}\)
\(M=\frac{2^{12}\cdot2^8}{2^{12}}\)
\(M=2^8=256\)
a) ( x + 5 )3 = -64
<=> ( x + 5 )3 = ( -4 )3
=> x + 5 = -4
<=> x = ( -4 ) - 5
<=> x = (-4) + (-5)
<=> x = - 9
Vậy x = -9
b) (2x - 3 )2 = 9
<=> ( 2x - 3 )2 = 32 hoặc (-3)2
=> 2x - 3 = 3 hoặc 2x - 3 = -3
<=> 2x = 3 + 3 hoặc 2x = (-3) + 3
<=> 2x = 6 hoặc 2x = 0
<=> x = 6 : 2 hoặc x = 0 : 2
<=> x = 3 hoặc x = 0
Vậy x € { 3 ; 0 }
a)(x+5)^3=-64
(x+5)^3=(-4)^3
x+5=-4
x=-9
b)(2x-3)^2=9
(2x-3)^2=3^2
2x-3=3
2x=6
x=3
a) ( x + 5 )3 = -64
<=> ( x + 5 )3 = ( -4 )3
=> x + 5 = -4
<=> x = ( -4 ) - 5
<=> x = (-4) + (-5)
=> x = - 9
hok tốt