b) \(x^3-6x^2+11x-12=0\)
\(\Leftrightarrow\)\(x^3-4x^2-2x^2+8x+3x-12=0\)
\(\Leftrightarrow\)\(x^2\left(x-4\right)-2x\left(x-4\right)+3\left(x-4\right)\)
\(\Leftrightarrow\)\(\left(x-4\right)\left(x^2-2x+3\right)=0\)
Ta có: \(x^2-2x+3\)
\(=\left(x-1\right)^2+2>0\)
\(\Rightarrow\)\(x-4=0\)
\(\Leftrightarrow\)\(x=4\)
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