Câu hỏi của Nguyễn Đăng Quyền

Question

A= (x^2-4y^2)(x^2-2xy+4y^2)(x^2+2xy+4y^2)

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Nguyễn Đức Trí · Accepted Answer

$A=\left(x^2-4y^2\right)\left(x^2-2xy+4y^2\right)\left(x^2+2xy+4y^2\right)$

$A=\left(x-2y\right)\left(x+2y\right)\left(x^2-2xy+4y^2\right)\left(x^2+2xy+4y^2\right)$

$A=\left(x-2y\right)\left(x^2+2xy+4y^2\right)\left(x+2y\right)\left(x^2-2xy+4y^2\right)$

$A=\left[x^3-\left(2y\right)^3\right]\left[x^3+\left(2y\right)^3\right]$

$A=\left[x^3-8y^3\right]\left[x^3+8y^3\right]$

$A=x^6-64y^6$

Câu trả lời: $A=\left(x^2-4y^2\right)\left(x^2-2xy+4y^2\right)\left(x^2+2xy+4y^2\right)$

$A=\left(x-2y\right)\left(x+2y\right)\left(x^2-2xy+4y^2\right)\left(x^2+2xy+4y^2\right)$

$A=\left(x-2y\right)\left(x^2+2xy+4y^2\right)\left(x+2y\right)\left(x^2-2xy+4y^2\right)$

$A=\left[x^3-\left(2y\right)^3\right]\left[x^3+\left(2y\right)^3\right]$

$A=\left[x^3-8y^3\right]\left[x^3+8y^3\right]$

$A=x^6-64y^6$