`a)[H^+]=2.10^[-4](M)`
`=>pH=-log(2.10^[-4])=3,7`
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`b)pH=2,6=>[H^+]=2,5.10^[-3](M)`
`=>[OH^-]=[10^[-14]]/[2,5.10^[-3]]=3,98.10^[-12](M)`
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`c)[H^+]=[0,05.2.0,2+0,1.0,3]/[0,2+0,3]=0,1(M)=10^[-1](M)`
`=>pH=1`
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`d)[OH^-]=0,06.0,3=0,018(M)=>[H^+]=[10^[-14]]/[0,018]=5,56.10^[-13](M)`
`=>[H^+]=[0,05.2.0,2+5,56.10^[-13]]/[0,2+0,3]=0,04(M)`
`=>pH=-log(0,04)=1,4`