Ta có: \(\dfrac{2x-4.36}{0.125}=0.25\cdot42.9-11.7\cdot0.25+0.25\cdot0.8\)
\(\Leftrightarrow\dfrac{2x-4.36}{\dfrac{1}{8}}=0.25\left(42.9-11.7+0.8\right)\)
\(\Leftrightarrow2x-4.36=\dfrac{1}{4}\cdot32\cdot\dfrac{1}{8}=1\)
\(\Leftrightarrow2x=5.36\)
hay x=2,68